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Forouzan Q19

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1 1 vote
In a leaky bucket used to control liquid flow, how many gallons of liquid are left in the
bucket if the output rate is 5 gal/min, there is an input burst of 100 gal/min for 12 s,
and there is no input for 48 s?

1 Answer

1 1 vote

The input burst = 100 gal/min = 1.667 gal/sec

The output rate = 5 gal/min = 0.0833 gal/sec

During the first 12 seconds, liquid left = (input – output) *12 = (1.667-0.0833)*12 = 19.004 gal

During the remaining 48 seconds, there is no input, so output = 0.0833*48 = 3.998 gal

Total liquid left = 19.004-3.998 = 15.006 gallons of liquid

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