4 votes 4 votes Each of $a, b, c$, and $d$ is a positive integer and is greater than $3.$ If $$ \frac{1}{a-2}=\frac{1}{b+2}=\frac{1}{c+1}=\frac{1}{d-3} $$ then which ordering of these four numbers is correct? $a\lt b\lt c\lt d$ $c\lt b\lt a\lt d$ $b\lt a\lt c\lt d$ $b\lt c\lt a\lt d$ Quantitative Aptitude goclasses2024-mockgate-12 goclasses quantitative-aptitude algebra 1-mark + – GO Classes asked Jan 19 • retagged Jan 25 by Lakshman Bhaiya GO Classes 486 views answer comment Share Follow See 1 comment See all 1 1 comment reply GauravRajpurohit commented Jan 22 reply Follow Share The number that has to be deduced is more obviously the greatest so that makes d then a then only they became equal and if you are adding something to make equal with others then obviously that number will be smaller so then b is smallest. 0 votes 0 votes Please log in or register to add a comment.
1 votes 1 votes We can take an example also: Let’s say we want this, $\frac{1}{9}=\frac{1}{9}=\frac{1}{9}=\frac{1}{9}$ $a,b,c\;\&\;d$ are positive integer and $>3$. $\therefore a=11, b=7,c=8,d=12$ So, $7<8<11<12$ $b<c<a<d$ $option\;D$ Akash 15 answered Jan 23 Akash 15 comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Best way is to eliminate the options a=b+4 we can conclude that b<a.Option A is not the answer a=c+3 .so c<a a=d-1 . from this we can say a<d. now we’ll compare b with c and d. b=c-1 means b<c. Now we got the relation among a,b,c i.e. b<c<a. And as a<d .so we can conclude that b<c<a<d i.e. Option D is answer Srken answered Jan 21 Srken comment Share Follow See all 0 reply Please log in or register to add a comment.