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How many unique four-digit numbers can be created using the digits 1, 3, 4, and 6, with each digit appearing only once, such that the resulting number is divisible by 3?
  • 🚩 Edit necessary | 👮 Mrityudoot | 💬 “7 was also in the numbers: 4 digit number w/o repetitions from{1,3,4,6,7}”
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Ans : Zero

Because for divisible by 3 , the sum of digits should be divisible by 3 but sum of 1+3+4+6=14 which is not multiple of 3.

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