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6 votes
6 votes

​​​​​​A person sold two different items at the same price. He made $10 \%$ profit in one item, and $10 \%$ loss in the other item. In selling these two items, the person made a total of

  1. $1 \%$ profit
  2. $2 \%$ profit
  3. $1 \%$ loss
  4. $2 \%$ loss
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5 Answers

3 votes
3 votes
Let sp of one =100

1.profit at 10%

Cp+.1cp=100

Cp=90.9

2.Loss at 10%

Cp-.1cp=100

.9cp=100

Cp=111.1

Total cp=202.01

Total sp=200

Loss=-2.01

%=(2.01/202)*100=~1%
3 votes
3 votes

If the first profit/loss is $x\%$ and second profit/loss is $y\%$ then overall profit/loss $\%$ is calculated as:

$\text{Total profit/loss=x+y+$\frac{xy}{100}\%$}$

  • we use $+$ sign if profit happens
  • we use $-$ sign if loss happens

It is given that the first $10\%$ profit is followed by $10\%$ loss so overall ;

Total profit/loss=$10+(-10)+\frac{10*(-10)}{100}\%\implies\frac{-100}{100}\%=-1\%$

we know that the minus sign indicates loss so overall $1\%$ loss made by the person.

Option $(C)$ is correct.

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