question on Supernetting

Question

You have the following four contiguous networks:

• $10.0.0.0/24$
• $10.0.1.0/24$
• $10.0.2.0/24$ 
• $10.0.3.0/24$

What is the supernet address that can represent all these networks?

Comments

rules of supernetting are:-

1) network id should be contiguous.

2) the networks to be combined should be a power of 2 and size of each network should be same.

3) first network id should be divisble by the total size of the supernet or first ip address must be divisible by the total no. of ip addresses to be combined in the supernet.

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supernet add=$10.0.0.0/22$

suernet mask= $255.255.252.0$

Answer 1

For all these 4 Networks , the NID(Network ID bits) = 24, HID(Host ID bits)=8.

To Supernet all these four network, you have to borrow 2 bits from NID.

After Supernetting, NID = 22 bits and HID = 10 bits.

Network ID of whole Network will be : 10.0.0.0/22

Comments

why we borrow 2 bits from networkID?can u pls explain more clearly?

 

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because this are 4 networks. so if we want to combine 4 networks we need 2 bits,