0 0 votes The polynomial \( x^4 - ax^3 + bx^2 - cx + 4 \) when divided by \( x - 2 \) leaves a remainder of 5 and when divided by \( x + 2 \) leaves a remainder of 11. Then \( b^2 = \)____ 25 36 9 4 Quantitative Aptitude go2026-quantitative-aptitude-shallow-1 polynomials quantitative-aptitude one-mark + – Shubham Sharma 2 268 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
2 2 votes Given: 1. \( P(2) = 2^4 - a(2^3) + b(2^2) - c(2) + 4 = 5 \) \[ 16 - 8a + 4b - 2c + 4 = 5 \] \[ 16 - 8a + 4b - 2c + 4 = 5 \] \[ 20 - 8a + 4b - 2c = 5 \] \[ -8a + 4b - 2c = -15 \quad \text{(1)} \] 2. \( P(-2) = (-2)^4 - a(-2)^3 + b(-2)^2 - c(-2) + 4 = 11 \) \[ 16 + 8a + 4b + 2c + 4 = 11 \] \[ 20 + 8a + 4b + 2c = 11 \] \[ 8a + 4b + 2c = -9 \quad \text{(2)} \] By solving these two equations: From (1): \[ -8a + 4b - 2c = -15 \quad \text{(3)} \] From (2): \[ 8a + 4b + 2c = -9 \quad \text{(4)} \] Adding (3) and (4): \[ -8a + 4b - 2c + 8a + 4b + 2c = -15 - 9 \] \[ 8b = -24 \] \[ b = -3 \] Finding \( b^2 \): \[ b^2 = (-3)^2 = 9 \] Correct Answer: C. 9 Shubham Sharma 2 answered Jul 25, 2024 Shubham Sharma 2 comment Share Follow 0 reply Please log in or register to add a comment.