2 2 votes What are the possible options for X? Computer Networks tcp computer-graphics + – merohan17 449 views answer comment Share Follow Print See 1 comment 1 1 comment reply js__ commented Oct 16, 2025 reply Follow flag X = 4001Y = 9501 0 0 replyShare Please log in or register to add a comment.
0 0 votes Answer will be 4001In C part, Receiver has sent ack 4001. It means receiver is expecting segment with sequence number 4001.so only possible value of X is 4001.for Y, if we assume that in C part, no data is sent by receiver then value of Y will be 9501. as FIN segment consumes 1 sequence number param_modi answered Oct 7, 2024 param_modi comment Share Follow See all 2 Comments 2 2 Comments reply merohan17 commented Oct 7, 2024 reply Follow flag But after phase C, client cannot send data so how does it make sense by using X = 4001 pure ACK segment? that's the doubt 0 0 replyShare param_modi commented Oct 7, 2024 reply Follow flag After receiving C segment, that is FIN, client has to send Ack of that (last ack). And all segments, including pure ack, must have a sequence number. Though in case of pure ack, sequence number will not be considered, and will be used again. 1 1 replyShare Please log in or register to add a comment.