Known vertices (in order marked known)$: \text{A B D F C G E}$
$$
\begin{array}{|c|c|c|c|}
\hline \text{Vertex} & \text{Known} & \text{Distance} & \text{Path} \\
\hline \text{A} & \text{Y} & 0 & \\
\hline \text{B} & \text{Y} & 2 & \text{A} \\
\hline \text{C} & \text{Y} & 7 & \text{A} \\
\hline \text{D} & \text{Y} & 4 & \text{B} \\
\hline \text{E} & \text{Y} & 12\;9 & \text{A C} \\
\hline \text{F} & \text{Y} & 6 & \text{D} \\
\hline \text{G} & \text{Y} & 8 & \text{F} \\
\hline
\end{array}
$$
Dijkstra's algorithm found the wrong path to some of the vertices. Computed path to $\mathrm{G}$ is $\mathrm{A}, \mathrm{B}, \mathrm{D}, \mathrm{F}, \mathrm{G}$ but shortest path is $\mathrm{A}, \mathrm{C}, \mathrm{E}, \mathrm{G}$. Computed path to $\mathrm{D}$ is $\mathrm{A}, \mathrm{B}, \mathrm{D}$ but shortest path is $\mathrm{A}, \mathrm{C}, \mathrm{E}, \mathrm{G}, \mathrm{D}$. Computed path to $\mathrm{F}$ is $\mathrm{A}, \mathrm{B}, \mathrm{D}, \mathrm{F}$ but shortest path is $\mathrm{A}, \mathrm{C}, \mathrm{E}, \mathrm{G}, \mathrm{D}, \mathrm{F}$.