1 1 vote Given the statement form below where $p, q, r, s$ are statement variables,$$\Biggl(\biggl(\Bigl((p \rightarrow q) \rightarrow(q \rightarrow r)\Bigl) \rightarrow(r \rightarrow s)\biggl) \vee p\Biggl) \wedge(p \rightarrow(p \rightarrow q)) \wedge p$$Which of the following is logically equivalent to the above?$p$$p \vee q$$p \wedge q$$p \rightarrow q$ Artificial Intelligence goclasses_da_ai_tw1 goclasses artificial-intelligence mathematical-logic two-marks + – GO Classes 608 views answer comment Share Follow Print See all 2 Comments 2 2 Comments reply chayancrroy3 commented Feb 8, 2025 reply Follow flag Please provide detailed solution. 0 0 replyShare GO Classes Support commented Mar 31, 2025 reply Follow flag @chayancrroy3 pls check the ans below 0 0 replyShare Please log in or register to add a comment.
4 4 votes GO Classes Support answered Mar 31, 2025 GO Classes Support comment Share Follow 0 reply Please log in or register to add a comment.
1 1 vote SVM answered Jan 23 SVM comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes Use the by-case method to solve it. Consider two cases: $\mathrm{P}=$ True , $\mathrm{P}=$ False. GO Classes answered Jan 10, 2025 GO Classes comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes p → ( p → q ) is equivalent to p → q because if p is True then p → q simplifies to q. p ∧ ( p → q) ∧ p simplifies to p ∧ q because p ∧ p is just p and p ∧ (p -> q) simplifies to p ∧ q the expression now becomes (((p→q)→(q→r))→(r→s))∨(p∧q) = (p∧q) OR (((p→q)→(q→r))→(r→s) so option D is correct anoushka11 answered Feb 10, 2025 anoushka11 comment Share Follow 0 reply Please log in or register to add a comment.