C programming\ predict the output

Question

main()
{
    int i=-1;
    -i;
    printf("i = %d, -i = %d \n",i,-i);
}

Comments

i=-1 -i=1

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my question is why that unary minus does not have any effect?

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Unary minus here is just displayed -ve value but no effect on the original value if we have i=-i then effect is shown

but -i is not stored --i = that i=i-1 representation so it is stored in i

Answer 1

main()
{
    int i=-1; // This will store -1 in i
    
    -i;  // This will not have any effect on i as you are not asigning that in i
    
    printf("i = %d, -i = %d \n",i,-i); // First will print value of i which is -1
                                       // Second will print value of -i which is 1
}

Hence the output will be -1 1