can we say that 3n+2=O(-n)?

Question

If f(n)=3n+2 then we can say that 3n+2<=(-4)(-n) .Can constant be negative in asymptotic notation?

Comments

No

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$f(n) = O(n)$ implies $f(n) \leq cn$, where $c$ is a "positive constant".

Answer 1

Example of Big O notation: f(x) ∈ O(g(x)) as there exists c>0 (e.g., c = 1) and x₀ (e.g., x₀ = 5) such that f(x) ≤ cg(x) whenever x ≥ x₀.

source https://en.wikipedia.org/wiki/Big_O_notation