0 0 votes We broke the least-squares error into three separate terms:$$\mathbf{E}\left[\left(y-f_\theta(x)\right)^2\right]=\mathbf{E}\left[(y-h(x))^2\right]+\mathbf{E}\left[\left(h(x)-f_\theta(x)\right)^2\right]+\mathbf{E}\left[\left(f_\theta(x)-\mathbf{E}\left[f_\theta(x)\right]\right)^2\right]$$where $y=h(x)+\epsilon, h(x)$ is the true model and $\epsilon$ is zero-mean noise. For each of the following terms, indicate its usual interpretation in the bias variance trade-off: Column 1Column 2(i) $\mathbf{E}\left[(y-h(x))^2\right]$a. Bias(ii)$\mathbf{E}\left[\left(h(x)-f_\theta(x)\right)^2\right]$b. Variance(iii) $\mathbf{E}\left[\left(f_\theta(x)-\mathbf{E}\left[f_\theta(x)\right]\right)^2\right]$c. Noise(i)-c, (ii)-b, (iii)-a(i)-c, (ii)-a, (iii)-b(i)-b, (ii)-c, (iii)-a(i)-c, (ii)-a, (iii)-b Machine Learning goclasses goclasses-da-course machine-learning bias-variance-tradeoff + – GO Classes 138 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.