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GO Classes DPP | C programming | Strings | ISRO 2020

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6 6 votes

What is the output of the code given below?

#include<stdio.h>
int main()
{
    char name[] = "satellites";
    int len;
    int size;
    len = strlen(name);
    size = sizeof(name);
    printf("%d", len * size);
    return 0;
}
  1. $100$
     
  2. $110$
     
  3. $40$
     
  4. $44$

 

2 Answers

4 4 votes

Answer: b) 110.
The above char array name can be written as below:
char[] name = {'s','a','t','e','T','l','i','t','e','s', '10' };

strlen gives no of characters in a string without the null in the end $=10$.
sizeof gives the no of characters(no of bytes specifically) in a string including the null at the end $=11$
So $11^ * 10=110$.

• edited by
1 flag:
✌ Edit necessary (Rajkumar Chaudhary)
3 3 votes
Answer is 110

Now notice that here in the char name[] = "satellites"; we didn’t defined the size of string / array of chars, so it automatically added the /0 char
So Strlen gives size 10 (excluding null char)
And sizeof gives size 11 (including null char)

If it would have been char name[10] = "satellites"; then there is no space for null char so the Strlen can result in undefined behavior — it could return a huge value or cause a crash.
Sizeof will simply return the size as 10

If it would have been char name[10] = "satellite"; then there is one space left as we have 9 char only so null char will automatically be added.
Strlen = 9
Sizeof = 10

If it would have been char name[10] = "sat"; then there is one space left as we have 9 char only so null char will automatically be added at 4th position.
Strlen = 3
Sizeof = 10
 
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