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3 Answers

4 4 votes

As \(n \to \infty\), the sum \(\sum_{i=1}^n \frac{1}{i^2}\) converges to a constant (proof), so it is \(\Theta(1)\).  Hence
\[
S = n \cdot \Theta(1) = \Theta(n).
\]
(we use asymptotic analysis to understand behavior for large values of \(n\), i.e., as \(n \to \infty\))


 

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