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GO Classes CS Test Series | Operating Systems | Subject Wise Test 3 | Question: 10

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Consider a system with $16$-bit virtual address space and a single-level page table. Page size is $16$ Byte and each page-table entry (PTE) occupies $1$ byte. The snapshot of the main memory for the process is given below:

 

  1. virtual address: 8192
  2. virtual address: 4095

What are the physical addresses corresponding to the given virtual addresses?

  1. (i) $256$,     (ii) $16015$
  2. (i) $1072$,   (ii) $ 65535$
  3. (i) $256$,     (ii) $65535$
  4. (ii) $1072$,  (ii) $16015$

1 Answer

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Physical address $\boldsymbol{=}$ frame No * page size $\boldsymbol{+}$ offset

(i) $8192=512 * 16+0$

(ii) $4095=255 * 16+15$

Page $512 \rightarrow$ Frame $67$

Page $255 \rightarrow$ Frame $100$

(i) $8192=67 * 16+0=1072$

(ii) $4095=1000 * 16+15=16015$
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