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GO Classes DPP | CN | NETWORK LAYER

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Consider three IP networks $A, B$, and $C$. Host $H \_A$ in network $A$ sends messages each containing $240$ bytes of application data to a host $H_{-} C$ in network $C$. The TCP layer prefixes a $20$ byte header to the message.

This passes through an intermediate network $B$. The maximum packet size, including the $20$ byte IP header, in each network is:

  • A: 1500 bytes
     
  • B: 120 bytes
     
  • C: 1500 bytes

The network $A$ and $B$ are connected through a 2 Mbps link, while $B$ and $C$ are connected by a $1$ Mbps link (bps = bits per second).

What is the rate at which application data is transferred to host $H_C$ ? Ignore errors, acknowledgments, and other overheads.

  1. $1.0$ Mbps
     
  2. $1.5$ Mbps
     
  3. $2.0$ Mbps
     
  4. $0.75$ Mbps

1 Answer

2 2 votes

To send one 240-byte application message...

- ...we had to transmit a total of $\mathbf{3 2 0}$ bytes across the network (due to fragmentation and the addition of three 20-byte IP headers and one 20-byte TCP header).

The efficiency is the ratio of application data to the total data transmitted:

  • Efficiency $=\frac{\text { Application Data }}{\text { Total Transmitted Data }}=\frac{240 \text { bytes }}{320 \text { bytes }}=0.75$ or $\mathbf{7 5} \%$

This means only $75\%$ of the data travelling through the bottleneck link is the actual application data you care about.

Application Data Rate $=1 \mathrm{Mbps} \times 0.75=0.75 \mathrm{Mbps}$

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