Register

GO Classes DPP | CN | SUBNETTING

661 views
4 4 votes

A network administrator is configuring four devices: a server (S), a printer (P), a workstation (W). and a router's interface (R). Their IP addresses are assigned as follows:

  • Server (S): $192.168.50.78$
     
  • Printer (P): $192.168.50.97$
     
  • Workstation (W): $192.168.50.65$
     
  • Router (R): $192.168.50.94$

All devices are configured with the subnet mask 255.255.255.224. Which of the following statements accurately describes the network configuration?

  1. The Server, Workstation, and Router are on the same subnet, but the Printer is on a different one.
     
  2. The Server and Printer are on one subnet, and the Workstation and Router are on another.
     
  3. All four devices are on the same subnet.
     
  4. The Printer and Router are on the same subnet, but the Server and Workstation are on different subnets.

1 Answer

1 1 vote

The key to this problem is the subnet mask: 255.255 .255 .224 .

  • The first three octets ( 255.255 .255 ) are straightforward. The last octet, 224 , is where the division happens.
     
  • In binary, 224 is 11100000 . This means the first 3 bits of the last octet are used for the network address, and the last 5 bits are for host addresses.
     
  • The "magic number" or block size for this subnet mask is $256-224=32$. This means our subnets will be in blocks of 32 addresses.

Starting from 0 , we can map out the subnets for the $192.168 .50 . x$ network:

  • Subnet 1: 192.168.50.0 (Network ID) to 192.168.50.31 (Broadcast ID)
     
  • Subnet 2: 192.168 .50 .32 to 192.168 .50 .63
     
  • Subnet 3: 192.168 .50 .64 to 192.168 .50 .95
     
  • Subnet 4: 192.168 .50 .96 to 192.168 .50 .127 
     
  • ... and so on.

Now, we just need to see which range each device's IP address falls into:

  • Server (S): 192.168.50.78
     
  • 78 is between 64 and 95 , so it's in Subnet 3.
     
  • Workstation (W): 192.168.50.65
     
  • 65 is between 64 and 95, so it's in Subnet 3.
     
  • Router (R): 192.168.50.94
     
  • 94 is between 64 and 95 , so it's in Subnet 3.
     
  • Printer (P): 192.168.50.97
     
  • 97 is between 96 and 127 , so it's in Subnet 4 .

The Server, Workstation, and Router all share the same network address ( 192.168 .50 .64 ), placing them on the same subnet. The Printer has a different network address ( 192.168.50.96 ), putting it on a separate subnet.

Therefore, option A is the correct choice.

Voting & Accepting an answer helps improve the community
Answer:
← Previous · GO Classes DPP | CN ...Next → · Computer Organizatio...
← Previous in category · GO Classes DPP | CN ...Next in category → · GO Classes DPP | CN ...
Position:
Show:

Related questions

3 3 votes
1 1 answer
322
322 views
GO Classes asked Oct 27, 2025
322 views
GO Classes DPP | CN | TOKEN BUCKET
A network router uses the token bucket algorithm to manage outgoing traffic. The bucket has a capacity of $500$ tokens, where each token corresponds to one packet. Tokens...
4 4 votes
1 1 answer
322
322 views
GO Classes asked Oct 27, 2025
322 views
GO Classes DPP | CN | FRAGMENTATION
A host needs to send a large IP datagram. The datagram's total data payload is $2400$ bytes. This datagram must be fragmented to cross a network link with a Maximum Trans...
5 5 votes
2 2 answers
440
440 views
GO Classes asked Oct 27, 2025
440 views
GO Classes DPP | CN | AIMD
A TCP connection is used for a critical file transfer. The connection starts with a congestion window ( cwnd ) of $1$ MSS and an initial slow start threshold ( ssthresh )...
5 5 votes
2 2 answers
477
477 views
GO Classes asked Oct 27, 2025
477 views
GO Classes DPP | CN | AIMD
A TCP connection is operating using the Additive Increase Multiplicative Decrease (AIMD) algorithm. At the beginning of the connection, the congestion window ( cwnd ) is ...