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Here given the value of theta 1 and -1 for 5x^4 and 1 respectively in the range of 0 and 1 here fixed parameter is theta so the likelihood function follows L(x/given θ = 1) is 5^n[sigma 1 to n xi^4](after applying summation on  and L(x/θ = -1) is 1 which is 1^n = 1 now comparing both L(x/1) / L(x/-1) is 1/ 5^nxi^4 so if L(x/1) >  L(x/-1) then the maximized likelihood is where theta is 1 and if L(x/1) < L(x/-1) then the maximised likelihood is theta = -1 so the answer is A and D !!

A standard problem for the understanding of how likelihood works
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