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1 1 vote

Identify Correct Asymptotic Behviour.

1 Answer

4 4 votes
If you keep substituting the terms, the recurrence becomes:

\[
T(n) = \Theta\!\left( \log n \left(\frac{4}{3}\right)^{k} \right),
\]

where

\[
k = \log_{3}\!\left( \log_{2} n \right).
\]

So the final answer is:

\[
T(n) = \left( \log_{2} n \right)^{\log_{3} 4}.
\]
 
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