Given grammar:
$E \rightarrow E \,+\, T \;\mid\; T \,*\, E \;\mid\; T$
$T \rightarrow T \,/\, F \;\mid\; F$
$F \rightarrow id$
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● Operator appearance by grammar level:
The operator $/$ appears in the rule for $T$:
$T \rightarrow T \,/\, F$
The operators $+$ and $*$ appear in the rules for $E$:
$E \rightarrow E \,+\, T \;\mid\; T \,*\, E$
Since $T$ is lower in the grammar hierarchy than $E$, any parsing involving $/$
must complete before any reductions that involve $+$ or $*$.
Thus $/$ binds more tightly than both $+$ and $*$ (i.e., it has higher precedence).
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● Associativity
$+$ is left-associative because $E \rightarrow E \,+\, T$ is left-recursive
$*$ is right-associative because $E \rightarrow T \,*\, E$ is right-recursive
$/$ is left-associative because $T \rightarrow T \,/\, F$ is left-recursive
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● Final Evaluation of statements:
A. * has higher precedence than + → False
B. / has higher precedence than * → True
C. + is left-associative → True
D. * is right-associative → True
Final Answer: $B, C, D$
