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Find bandwidth.

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Consider a point to point link 50Kms in length.At what bandwidth would propagation delay(at the speed of light) equal to transmit delay for 100 byte packets ? What about 512 byte packets?

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As Transmission time(TT)=Data size/Bandwidth and Propagation time(PT)=Distance/velocity.

given that TT=PT we can conclude that  Bandwidth(BW)=(Data size*Velocity)/distance

For 100 bytes packet BW=(100bytes*3*108ms-1)/50*103m=4.8Mbps

and 512 bytes packet BW=(512bytes*3*108ms-1)/50*103m=24.576Mbps

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