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3 3 votes

Consider line number $\textbf{4}$ of the following C-program.
 

int main() { /* Line 1 */
    int value, result; /* Line 2 */
    value = 100; /* Line 3 */
    result = value @ 5; /* Line 4 */
    printf("%d", result); /* Line 5 */
}


Identify the compiler's response while creating the object-module:

  1. Only a syntactic error 
     
  2. Only a semantic error 
     
  3. Only a lexical error 
     
  4. Both lexical and syntactic errors

3 Answers

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Analyzing Line 4: $\verb|result = value @ 5;|$

When the compiler's lexical analyzer (scanner) reaches the character $\verb|@|$ in Line $4$, it attempts to group it with adjacent characters to form a valid C token:

  • It checks if $\verb|@|$ is a valid single-character operator. It is not.
     
  • It checks if it is part of a multi-character operator (like $\verb|==|$, $\verb|!=|$, etc.). It is not.
     

Since the character $\verb|@|$ is not a valid character for forming any legal token in C (it is not part of an identifier, keyword, constant, or recognized operator), the scanner cannot classify it.

This failure to recognize and generate a legal token occurs during the lexical analysis phase and is classified as a lexical error.

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