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1 Answer

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Initial dictionary creation:

$$
A=\{0: 0,1: 1,2: 4\}
$$


Reference and copy:

$$
B=A
$$

$B$ refers to the same dictionary object as $A$.

$C = A.copy()$

$C$ is a shallow copy, so it refers to a different dictionary object.


Updates:

$$
\begin{aligned}
& A[3]=9 \rightarrow \text { modifies } A(\text { and } B) \\\\
& B[4]=16 \rightarrow \text { modifies } A(\text { and } B) \\\\
& C[5]=25 \rightarrow \text { modifies only } C
\end{aligned}
$$


Final contents:

$$
\begin{aligned}
& A=\{0: 0,1: 1,2: 4,3: 9,4: 16\} \rightarrow \text { length } 5 \\\\
& B=\text { same as } A \rightarrow \text { length } 5 \\\\
& C=\{0: 0,1: 1,2: 4,5: 25\} \rightarrow \text { length } 4
\end{aligned}
$$


Final output:

$$
\verb|554|
$$

Answer:
Position:
Show:

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