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GO Classes DPP | PYTHON & DSA |PYTHON

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Given a list of integers numbers $=[1,2,3,4,5,6]$, which of the following list comprehensions correctly creates a new list containing the squares of only the even numbers?

  1. numbers.map(lambda $x$ : $x^{\star \star} 2$ if $x \% 2==0$ )
     
  2. $x^{\star \star} 2$ for $x$ in numbers if $x \% 2==0]$
     
  3. $[x^{\star \star} 2$ if $x \% 2==0$ for $x$ in numbers $]$
     
  4. $\left[x^{\wedge} 2\right.$ for $x$ in numbers if $x \% 2==0$ ]

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A. numbers.map(lambda $\mathrm{x}: \mathrm{x} 2$ if $\mathrm{x} \% 2==0$ )**

  • INCORRECT: Python lists do not have a .map() method. You would need to use the built-in map() function.

B. $[\mathrm{x} 2 \text { for } \mathrm{x} \text { in numbers if } \mathrm{x} \% 2==0]^{* *}$

  • CORRECT: This follows the standard syntax: [expression for item in iterable if condition]. It correctly filters for even numbers and squares them.

C. $[x 2 \text { if } x \% 2==0 \text { for } x \text { in numbers }]^{* *}$

  • INCORRECT: When using if for filtering, it must come after the for clause. The if before the for is only used for ternary expressions (e.g., x if condition else y).

D. $\left[x^{\wedge} 2\right.$ for $x$ in numbers if $\left.x \% 2==0\right]$

  • INCORRECT: In Python, ${ }^{\wedge}$ is the bitwise XOR operator. The exponentiation operator is ** .
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