3 3 votes A computer system contains $\mathbf{10}$ IDENTICAL MAGNETIC TAPE DRIVES. There are $N$ processes currently running in the system, and each process has a MAXIMUM NEED of $\mathbf{3}$ DRIVES to complete its execution.What is the SMALLEST VALUE of $N$ such that the system could potentially enter a DEADLOCK state?$4$ $5$ $6$ $11$ Operating System goclasses operating-system goclasses-cs-dpp goclasses-cs-dpp-day-170 goclasses-os-practice-questions + – GO Classes 395 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
1 1 vote \begin{aligned} & N \times(3-1) \geq 10 \\\\ & 2 N \geq 10 \\\\ & N \geq 5 \end{aligned} GO Classes answered Jan 2 GO Classes comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes So what we got here system containing 10 identical magnetic tape drivers +N processes running in the system+maximum need for each process is 3 drivers question: smallest value of n that can cause deadlockSolutionwe can use the hold and wait concept to imagine a procees will complete if it has 3 resources so lets hold with 3-1=2so 5*2=10 and we have no more resources this lead to deadlock so the Answer is 5 rajeshwaren answered Jan 8 rajeshwaren comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes 5 JAY_THAKAR answered Jan 9 JAY_THAKAR comment Share Follow 0 reply Please log in or register to add a comment.