$\{b, c, d, \$\}$
Since $S \rightarrow A B$, $\operatorname{FOLLOW}(\mathrm{A})$ contains $\operatorname{FIRST}(\mathrm{B})$. Because $B$ is nullable ( $\mathrm{B} \rightarrow \mathrm{C} \rightarrow \epsilon$ ), $\operatorname{FOLLOW}(\mathrm{A})$ also inherits $\operatorname{FOLLOW}(\mathrm{S})$, which is $\{\$\}$.