Let x be the volume of water poured initially.
Concentration of milk = $\frac{300-x}{300}$
Volume of solution removed = 2x
Volume of solution remaining = 300 - 2x
Remaining milk = (300 - 2x) x $\frac{300-x}{300}$
Final volume of milk = 0.72 x 300 = 216
Hence,
(300 - 2x) x $\frac{300-x}{300}$ = 216
This gives
$x^{2} - 450x + 12600 = 0$
x = 420 or 30
but since volume removed i.e. 2x can't be >300, therefore water poured initially was 30 litres.