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Consider an Adjacency List representation of a directed graph $G=(V, E)$ with $n$ vertices and $m$ edges, implemented using Python's $\verb|dict|$ where keys are vertex IDs and values are $\verb|lists|$ of neighbor vertex IDs.

Which of the following statements regarding the time complexity of operations on this structure are TRUE?

  1. Finding if a specific edge $(u, v)$ exists takes $O(1)$ time in the worst case.
     
  2. Computing the out-degree of a vertex $u$ takes $O(1)$ time if using Python's $\verb|len(adj[u])|$.
     
  3. Computing the in-degree of a vertex $u$ takes $O(n+m)$ time in the worst case.
     
  4. Performing a Breadth-First Search (BFS) starting from a source vertex $s$ takes $O(n+m)$ time.

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Answer: B, C, and D

 

Explanation

  • A. Finding if a specific edge $\mathbf{(u, v)}$ exists takes $\mathbf{O(1)}$ time in the worst case.
    • This is False. In an adjacency list implemented with a standard list for neighbors, finding $v$ in $u$'s neighbor list requires a linear scan, which takes $O(\text{out-degree}(u))$ time in the worst case, not $O(1)$.
  • B. Computing the out-degree of a vertex $\mathbf{u}$ takes $\mathbf{O(1)}$ time if using Python's $\mathbf{len(adj[u])}$.
    • This is True. Accessing adj[u] in a Python dictionary is $O(1)$ on average, and getting the length of a list using len() is also an $O(1)$ operation.
  • C. Computing the in-degree of a vertex $\mathbf{u}$ takes $\mathbf{O(n + m)}$ time in the worst case.
    • This is True. To find the in-degree of a specific vertex $u$, one must iterate through all adjacency lists of all vertices to count how many times $u$ appears as a neighbor. This involves checking every edge in the graph, resulting in an $O(n+m)$ time complexity.
  • D. Performing a Breadth-First Search (BFS) starting from a source vertex $\mathbf{s}$ takes $\mathbf{O(n + m)}$ time.
    • This is True. The standard time complexity for a BFS on an adjacency list representation is $O(V + E)$, which corresponds to $O(n+m)$ in this case, as every vertex and every edge is visited once.
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