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GO Classes DPP | GATE CS | C Programming | Logical Operators

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11 11 votes

What is the output of the following code?

#include <stdio.h>

int main() {
    int a = 5, b = 10;
    printf("%d", a > b || b > 0);
    return 0;
}

2 Answers

1 1 vote

Here, $\texttt{a = 5}$ and $\texttt{b = 10}$.

The expression inside $\texttt{printf()}$ is $\texttt{a > b || b > 0}$.

Now, $\texttt{a > b}$ means $\texttt{5 > 10}$, which is false, so its value is $0$.

Also, $\texttt{b > 0}$ means $\texttt{10 > 0}$, which is true, so its value is $1$.

Therefore, the expression becomes $0 \ || \ 1$.

In C, logical OR $\texttt{||}$ gives $1$ if at least one condition is true.

So, $0 \ || \ 1 = 1$.

Therefore, the output is $\texttt{1}$.

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