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GO Classes DPP | GATE CS | C Programming | Type Conversion

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8 8 votes

What is the output of the following code?

#include <stdio.h>

int main() {
    float x = 5 / 2;
    printf("%.1f", x);
    printf(" ");
    float y = 5.0 / 2;
    printf("%.1f", y);
    return 0;
}
  1. $\verb|2.5 2.0|$
     
  2. $\verb|2.0 2.5|$ 
     
  3. $\verb|3.0 3.0|$ 
     
  4. Compilation error

2 Answers

1 1 vote

In the statement $\texttt{float x = 5 / 2;}$, both $\texttt{5}$ and $\texttt{2}$ are integers.

So, integer division is performed first.

Thus, $\texttt{5 / 2 = 2}$.

Then this integer value $\texttt{2}$ is stored in the float variable $\texttt{x}$, so $\texttt{x = 2.0}$.

Now, in the statement $\texttt{float y = 5.0 / 2;}$, $\texttt{5.0}$ is a floating-point value.

So, floating-point division is performed.

Thus, $\texttt{5.0 / 2 = 2.5}$.

Therefore, the output is $\texttt{2.0\ 2.5}$.

Answer: B. $\texttt{2.0\ 2.5}$

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