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GO Classes DPP | GATE CS | C Programming | Type Conversion

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7 7 votes

What is the output of the following code?

#include <stdio.h>

int main() {
    int a = 5, b = 2;
    float x = a / b + 0.5;
    printf("%.1f", x);
    return 0;
}

2 Answers

1 1 vote

Here, $\texttt{a = 5}$ and $\texttt{b = 2}$.

In the expression $\texttt{a / b + 0.5}$, first $\texttt{a / b}$ is evaluated.

Since both $\texttt{a}$ and $\texttt{b}$ are integers, integer division is performed.

So, $\texttt{5 / 2 = 2}$.

Now the expression becomes $\texttt{2 + 0.5}$, which gives $\texttt{2.5}$.

Therefore, the output is $\texttt{2.5}$.

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