122 views
1 1 vote

Consider the following Python code:

data = {"a": 2, "b": 3}

for key in ["a", "c", "b", "a"]:
 data[key] = data.get(key, 0) + 1

print(data)

What is the output of the code above?

  1. {'a': 4, 'b': 4, 'c': 1}
  2. {'a': 3, 'b': 4, 'c': 1}
  3. {'a': 4, 'c': 1, 'b': 4}
  4. {'a': 2, 'b': 3, 'c': 1}

1 Answer

0 0 votes

The dictionary starts as:

{'a': 2, 'b': 3}

For $\texttt{"a"}$, the value becomes $\texttt{3}$.

For $\texttt{"c"}$, the key does not exist, so $\texttt{data.get("c", 0)}$ gives $\texttt{0}$. Then $\texttt{c}$ becomes $\texttt{1}$.

For $\texttt{"b"}$, the value becomes $\texttt{4}$.

For $\texttt{"a"}$ again, the value becomes $\texttt{4}$.

{'a': 4, 'b': 4, 'c': 1}

Correct Option: A

Answer:
Position:
Show:

Related questions

1 1 vote
2 2 answers
183
183 views
GO Classes asked Jun 3
183 views
Consider the following Python code:nums = [1, 2, 3, 4, 5] result = [n * 2 if n % 2 == 0 else n + 1 for n in nums if n 2] print(result)What is the output of the code abov...
0 0 votes
1 1 answer
128
128 views
GO Classes asked Jun 3
128 views
Consider the following Python code:text = "bookkeeper" count = 0 for i in range(len(text) - 1): if text[i] == text[i + 1]: count += 1 print(count)What is the output of th...
0 0 votes
1 1 answer
125
125 views
GO Classes asked Jun 3
125 views
Consider the following Python code:def update(nums): nums.append(nums[-1] + 1) nums = nums[1:] nums[0] = 99 return nums values = [3, 4, 5] result = update(values) print(v...
0 0 votes
1 1 answer
125
125 views
GO Classes asked Jun 3
125 views
Consider the following Python code:items = [10, 20, 30, 40, 50] part = items[1:4] part = 99 items += part[0] print(items, part)What is the output of the code above?[10,...