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GO Classes DPP | GATE CS | C Programming | Nested Loops

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12 12 votes

What is the output of the following code?

#include <stdio.h>

int main() {
    int i, j, count = 0;

    for (i = 1; i <= 3; i++) {
        for (j = 1; j <= i; j++) {
            count = count + j;
        }
    }

    printf("%d", count);
    return 0;
}

2 Answers

3 3 votes

For $\texttt{i = 1}$, the inner loop runs for $\texttt{j = 1}$, so $\texttt{count = 0 + 1 = 1}$.

For $\texttt{i = 2}$, the inner loop runs for $\texttt{j = 1, 2}$, so $\texttt{count = 1 + 1 + 2 = 4}$.

For $\texttt{i = 3}$, the inner loop runs for $\texttt{j = 1, 2, 3}$, so $\texttt{count = 4 + 1 + 2 + 3 = 10}$.

Therefore, the output is $\texttt{10}$.

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