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GO Classes DPP | GATE CS | C Programming | Static Local Variable

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8 8 votes

What is the output of the following code?

#include <stdio.h>

void fun() {
    static int x = 1;

    x = x + 2;

    printf("%d ", x);
}

int main() {
    fun();
    fun();
    fun();

    return 0;
}
  1. $\texttt{3\ 3\ 3}$
     
  2. $\texttt{3\ 5\ 7}$
     
  3. $\texttt{1\ 3\ 5}$
     
  4. $\texttt{2\ 4\ 6}$

2 Answers

3 3 votes

Option B

1 1 vote

Here, $\texttt{x}$ is a static local variable.

A static local variable is initialized only once and keeps its value between function calls.

Initially, $\texttt{x = 1}$.

In the first call, $\texttt{x = 1 + 2 = 3}$, so it prints $\texttt{3}$.

In the second call, $\texttt{x}$ starts from old value $\texttt{3}$.

So, $\texttt{x = 3 + 2 = 5}$, and it prints $\texttt{5}$.

In the third call, $\texttt{x}$ starts from old value $\texttt{5}$.

So, $\texttt{x = 5 + 2 = 7}$, and it prints $\texttt{7}$.

Therefore, the output is $\texttt{3\ 5\ 7}$.

Answer: B

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