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GO Classes DPP | GATE DA | Python Programming | List Comparison

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1 1 vote

Consider the following Python code:

a = [1, 3]
b = [2, 2]
c = [1, 2, 3, 4]
d = [1, 2, 5, 0]
e = [1, 2]
f = [1, 2, 0]

print(a < b, c < d, e == f)

What is the output of the code above?

  1. True False False
  2. True True False
  3. False True False
  4. True True True

2 Answers

2 2 votes

Lists are compared element by element from left to right.

For $\texttt{a < b}$:

[1, 3] < [2, 2]

Python compares the first elements. Since $\texttt{1 < 2}$ is true, the result is true.

For $\texttt{c < d}$:

[1, 2, 3, 4] < [1, 2, 5, 0]

The first two elements are equal. Then Python compares $\texttt{3}$ and $\texttt{5}$.

3 < 5

So this result is also true.

For $\texttt{e == f}$:

[1, 2] == [1, 2, 0]

These lists do not have the same length, so they are not equal.

Therefore, the output is:

True True False

Correct Option: B

0 0 votes

Bilkul sahi, aapne bilkul sahi notice kiya! 🎯 List comparison ka yeh rule thoda alag aur interesting hai. Python mein jab hum < (less than) ya > (greater than) use karte hain, toh comparison ko Lexicographical Comparison (yaani dictionary order) kehte hain.

Chalo is poori theory ko ek dum simple points mein summarize karte hain:

📝 List Comparison Ka Poora Saar (Summary)

Python left-to-right chalte hue pehle aise index ko dhoondta hai jahan dono lists ke elements alag (different) hon. Jaise hi use pehla different element milta hai, wo poori list ka faisla wahin kar deta hai:

  1. Pehle different element par faisla:

    • [1, 3] < [2, 2]

    • Pehle hi index (index 0) par elements alag hain: 1 aur 2. Kyunki 1 < 2 hota hai, isliye aage check kiye bina seedhe answer True aa gaya. (Baaki ke elements chahe kuch bhi hon, unse koi farq nahi padta).

  2. Barabar elements ko skip karna:

    • [1, 2, 3, 4] < [1, 2, 5, 0]

    • Index 0 aur index 1 par elements bilkul same hain (1 aur 2). Python aage badhega.

    • Index 2 par use pehla different pair mila: 3 aur 5. Kyunki 3 < 5 hota hai, isliye poori list ka result True ho gaya.

  3. Agar ek list khatam ho jaye (Length ka farq):

    • Agar saare elements same hain par ek list choti hai, toh choti list ko hamesha chota (<) maana jata hai.

    • Jaise: [1, 2] < [1, 2, 0] ka result True hoga kyunki pehli list pehle khatam ho gayi.

    • Aur == ke liye toh size aur elements dono exact same hone chahiye, isliye [1, 2] == [1, 2, 0] ka result False aaya.

    • so option b is correct. 

    •  

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