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GO Classes DPP | GATE DA | Python Programming | Args Zip Lambda

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Consider the following Python code:

def process(*nums):
    f = lambda x, y: x + 2 * y
    pairs = zip(nums, nums[1:])
    return tuple(f(a, b) for a, b in pairs)

print(process(1, 3, 5, 7))

What is the output of the code above?

  1. (4, 8, 12)
  2. (7, 13, 19)
  3. [7, 13, 19]
  4. (5, 9, 13)

1 Answer

0 0 votes

The parameter $\texttt{*nums}$ collects all arguments into a tuple.

nums = (1, 3, 5, 7)

The lambda function is:

lambda x, y: x + 2 * y

Now:

zip(nums, nums[1:])

This forms pairs from consecutive values.

(1, 3), (3, 5), (5, 7)

Apply the lambda function on each pair:

f(1, 3) = 1 + 2 * 3 = 7
f(3, 5) = 3 + 2 * 5 = 13
f(5, 7) = 5 + 2 * 7 = 19

The result is converted into a tuple.

(7, 13, 19)

Correct Option: B

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