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GO Classes DPP | GATE DA | Python Programming | Zip Function

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2 2 votes

Consider the following Python code:

letters = ["A", "B", "C"]
numbers = [1, 2, 3]

pairs = list(zip(letters, numbers))

print(pairs[1], pairs[-1][0] + str(pairs[0][1]))

What is the output of the code above?

  1. ('A', 1) C1
  2. ('B', 2) C1
  3. ('B', 2) A3
  4. ['B', 2] C1

1 Answer

0 0 votes

The $\texttt{zip()}$ function pairs elements from the given iterables position-wise.

letters = ["A", "B", "C"]
numbers = [1, 2, 3]

So:

pairs = [('A', 1), ('B', 2), ('C', 3)]

Now $\texttt{pairs[1]}$ gives the second tuple.

pairs[1] = ('B', 2)

Also, $\texttt{pairs[-1]}$ gives the last tuple.

pairs[-1] = ('C', 3)
pairs[-1][0] = 'C'

And $\texttt{pairs[0][1]}$ gives $\texttt{1}$.

pairs[-1][0] + str(pairs[0][1]) = 'C' + '1' = 'C1'

Therefore, the output is:

('B', 2) C1

Correct Option: B

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