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GO Classes DPP | GATE CS | C Programming | Null Character in String

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6 6 votes

What is the output of the following code?

#include <stdio.h>

int main() {
    char str[] = {'C', 'S', 'E', '\0', 'X'};

    printf("%s %c", str, str[4]);

    return 0;
}
  1. $\texttt{CSE X}$
     
  2. $\texttt{CSEX X}$
     
  3. $\texttt{CSE \textbackslash0}$
     
  4. $\texttt{Compilation error}$

2 Answers

0 0 votes

 

Here, $\texttt{str}$ is a character array.

The characters are:

$\texttt{str[0] = 'C'}$
$\texttt{str[1] = 'S'}$
$\texttt{str[2] = 'E'}$
$\texttt{str[3] = '\textbackslash0'}$
$\texttt{str[4] = 'X'}$

When a character array is printed using $\texttt{\%s}$, printing continues only until the null character $\texttt{'\textbackslash0'}$.

So, $\texttt{\%s}$ prints only:

$\texttt{CSE}$

The character $\texttt{'X'}$ is present in the array, but it comes after $\texttt{'\textbackslash0'}$, so it is not printed as part of the string.

But $\texttt{str[4]}$ directly accesses the character at index $\texttt{4}$.

So, $\texttt{str[4] = 'X'}$
 

$\therefore$ Output :

$\texttt{CSE X}$
 

Answer: A

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