3 3 votes Consider the following Python code:def virfib_sq(n): print(n) if n <= 1: return n return (virfib_sq(n - 1) + virfib_sq(n - 2)) ** 2 r1 = virfib_sq(1)What would be the output? Programming in Python goclasses goclasses-da-dpp goclasses-da-dpp-day-213 programming-in-python goclasses-python-&-dsa-practice-questions output recursion numerical-answers + – GO Classes 226 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
1 1 vote The function is called as:r1 = virfib_sq(1)First, the function prints $\texttt{n}$.print(n)Since $\texttt{n = 1}$, Python prints:1Then the base case is true:if n <= 1: return nSo the function returns $\texttt{1}$ and stores it in $\texttt{r1}$. But $\texttt{r1}$ is not printed.Final output:1 GO Classes answered Jul 1 GO Classes comment Share Follow 0 reply Please log in or register to add a comment.