2 2 votes Consider the following Python code:def insert_items(s, before, after): index = 0 while index < len(s): if s[index] == before: s.insert(index + 1, after) index += 1 index += 1 return s large_s = [1, 4, 8] large_s2 = insert_items(large_s, 4, 4) large_s3 = insert_items(large_s2, 4, 6) print(large_s3) print(large_s3 is large_s)What is the output of the code above?[1, 4, 6, 4, 6, 8] True[1, 4, 4, 8] True[1, 4, 6, 4, 8] True[1, 4, 6, 6, 4, 8] False Data Structures goclasses goclasses-da-dpp goclasses-da-dpp-day-215 python-&-dsa goclasses-python-&-dsa-practice-questions output list + – GO Classes 131 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
0 0 votes Initially:large_s = [1, 4, 8]First call:large_s2 = insert_items(large_s, 4, 4)This inserts $4$ after every existing $4$.large_s = [1, 4, 4, 8]Now second call:large_s3 = insert_items(large_s2, 4, 6)This inserts $6$ after each $4$.large_s3 = [1, 4, 6, 4, 6, 8]The function modifies the same original list in place, so:large_s3 is large_sis $\texttt{True}$.Final output:[1, 4, 6, 4, 6, 8] True GO Classes answered Jul 3 GO Classes comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes Answer: A Meticulous_March answered Jul 6 Meticulous_March comment Share Follow 0 reply Please log in or register to add a comment.