GO Classes DPP | GATE CS | Data Structures | Infix Postfix

Answer 1

First convert the bracketed parts:

$\texttt{(b - c)}\rightarrow$ $\texttt{b c -}$

$\texttt{(e - f)}\rightarrow$ $\texttt{e f -}$

$\texttt{(e - f) / g}\rightarrow$ $\texttt{e f - g /}$

$\texttt{((e - f) / g + h)}\rightarrow$ $\texttt{e f - g / h +}$

Now combine:

$\texttt{a + (b - c)}$

becomes:

$\texttt{a b c - +}$

And:

$\texttt{d * ((e - f)/g + h)}$

becomes:

$\texttt{d e f - g / h + *}$

So the complete postfix expression is:

$\texttt{a b c - + d e f - g / h + * -}$

Correct option : A

Answer 2

do first all brackets bc- , ef- then ef-g/ 

then ef-g/h+ 

now for def-g/h+*

now add and subtraction have same associativity but from left to right so first addition will be formed 

so final A. a b c - + d e f - g / h + * -

Answer 3

Ans is A

Answer 4

Here is the Details Explanation