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GO Classes DPP | GATE CS, DA | Algorithms | Master's Theorem

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Given:

$T(n)=3T(n/5)+(\log n)^2$

Using the Master Theorem:

$a=3$, $b=5$, and $f(n)=(\log n)^2$

Calculate:

$n^{\log_b a}=n^{\log_5 3}$

Since $(\log n)^2$ grows slower than $n^{\log_5 3}$, this is Master Theorem Case $1$.

Therefore:

$T(n)=\Theta(n^{\log_5 3})$


Answer: B $O(n^{\log_5 3})$

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