ISI Maths

Question

11(V1+V2)15T

Comments

something wrong in this Question. i think Given value 1 mile =52800 is wrong here.

Answer 1

Total distance required to cover by one train is 2L.

 

By considering one train at rest then speed of other train is (v1+v2) mile/hour = $\frac{52800}{3600}$(v1+v2)$\frac{feet}{sec}$

=$\frac{44}{3}$(v1+v2)$\frac{feet}{sec}$

As speed=$\frac{Distance}{Time}$

$\frac{44}{3}$(v1+v2)=$\frac{2L}{T}$

 

So,L=$\frac{22}{3}$(v1+v2)

Comments

Sir, I think u missed something somewhere..

52800/3600(v1+v2)= 2L/T

88/6(v1+v2)=2L/T

44/6(v1+v2)T=L

L= 22/3 (v1+v2)T

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i had one mistake only in last line.i forgot to cancel 9.updated now.

Answer should be none of these.