ace test series

Question

A TCP sender choses its initial  sequence number as 1093 and sends 1460
bytes of data to the reciever The reciever has an initial  sequence number
391 and acknowledges the data of sender The acknowledgment number
sent by the receiver is_______ ?

Comments

2553

Answer 1

solution says 2554..
mine is 2553 ..please help!!!!

You got correct till end we miss somthing in last

idea is: since data send = 1460 B  

so 1093+ 1460 = 2553 till here reciver got data  since sequence no. of each byte in segment

so he request for 2554  i.e. he want data from 2554 . ack means give me data from 2554

Comments

Acknowledge number in this protocol means next which byte receiver wants to receive.

So 2554

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correct me if i am wrong ..

here the sequence number is starting from 1093 and the data is of length 1460

so if we add two then 2553..since the sequence number is starting from 1093(includes)

then the sequence number of the last byte receives by the receiver is 2553-1=2552

the bytes of the data send by the receiver has to be 1460 but if the reciver receives till 2553 and sends ack number ...it is gonna be 1461

so the ack number send by the receiver has to be 2553

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If a segment has 2 bytes of data nad initial sequence number is 5,

Then byte numbers contained in the segment will be 5 and 6 .

Receiver acknowledges 5,6 and expects 7

So ack coming from receiver side = 7

From the same logic 2553 will be the answer.

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Exactly my reasoning. That's why i think it next ACK should be 2553.