Explain how it has come in detali? #Algo

Question

Answer 1

Outer "i" loop is running 100 times which is constant

For each of the value of "i" inner "j" loop runs n times

"k" loop runs "j" times which inetern runs n times

Therefore the total complexity is O(n^2)

Answer 2

You can simply replace j with n u will get two loops to n so O(n^2)