page fault closed

Question

in a paged memory page hit ratio is 0.2,time required to access a page in memory=10ns, time taken to access secondary memory=100ns. what is EMAT

my expression: pagehit(memory access time)+page fault(secondary memory access time+memory access time)
=10ns+0.8(100ns)=90ns
isnt it correct?
answer given is 82.
it means they calculated it as 0.2(10)+0.8(100) =82
but they gave only time taken to access secondary memory, we also need to make another primary memory access to get the required page.
please explain

Comments

it means pagefault(page table access time+secondary memory access time)?
i mean the memory access time corresponds to page table?

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For this question, simply memory access time

And as no information regarding PT is given, so we will assume that PT access time is  already included in Memory AT.

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ok,thank you :)