GATE Overflow | Programming | Test 1 | Question: 3

Question

What will be the output of the following code?

#include <stdio.h> 
#include <string.h>
int main() 
{ 
	char string[] = "Hello"; 
	if(sizeof(string) <= strlen(string))
		printf("1");
	printf("0");
}

______

Answer 1

char string[] = "Hello"; //'\0' is added by compiler at end of string literals
sizeof(string) = (5+1) = 6  //+1 to store EndOfString char '\0'.
strlen(string) = 5

if(sizeof(string) <= strlen(string)) returns False so it wont print 1 and finally it will print 0.

Answer 2

Answer will be Zero as strlen() function always gives the actual length of string excluding '\0', but '\0' is always present at the end of string taking space in memory so it is counted in sizeof operator.

Answer 3

0 because 

sizeof(string) = strlen(string)

Comments

No. sizeof includes null char at the end but strlen ignores it.

Answer 4

it will print 0 as a o/p

Answer 5

Sizeof(String) = 6

Strlen(String) = 5

Since if condition fails answer = 0

Answer 6

The condition fails and print 0