GATE Overflow | Programming | Test 1 | Question: 29

Question

What will be the output of the following code?

#include <stdio.h>
#include <string.h>
int main()
{
    struct mystruct{
        char *name;
        unsigned int age;
    };
    struct mystruct st1 = {"Ram", 12};
    printf("%lu %u", strlen(st1.name), st1.age);
}

• A. 4 12
• B. 3 12
• C. compile error
• D. run time error

Answer 1

st1.name = "Ram"
strln(st1.name) = 3

st1.age = 12

It will print 3 12

Comments

what about the format specifiers? 

u is a specifier meaning "unsigned decimal integer".

l is a length modifier meaning "long".

---

can we declare or define structure inside main ?

---

@Digvijay Pandey sir, name is character type ,then strlen should be 4 ???

 

---

To woh null ki value add nhi krega

Answer 2

str1="Ram",12

str1.name =Ram

str1.age=12

strlen(Ram)=3

so 3 12  will be printed

option(B) is correct

it will not calculated NULL as a character.

Comments

why this not take NULL as char....can u explain plzzzzzzzzzzzzzz

---

null value is calulated by compiler automatically.

---

only sizeof() method calcuates the null not strlen