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If the initial sequence number is 1 and it is incremented by 256000 every 2 sec, how long does it take for counter to wrap around?
(A) 33,554 seconds
(B) 44,554 seconds
(C) 33,555 seconds
(D) 44,555 seconds 

 

1 Answer

Best answer
3 3 votes

 Initial sequence number is 1 and it is incremented by 256000 every 2 sec,
 We know that in TCP sequence no field is 32 bit long so total 232  sequence no are possible
  now come 2 the question 
256000 sequence no are consumed in 2 sec
so  232  sequence no can be consume in 232 *2 /256000 =33554.432 =33555 sec requires to wrap around
Hence option C is correct.

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