Compiler Inherited Attribute

Question

Consider the following translation rules:
\[
\begin{array}{l}
\mathrm{S} \rightarrow \mathrm{~A} \quad\{\mathrm{~A} . \text { val }=0\} \\
\mathrm{A} \rightarrow \mathrm{~A}_{1} 1 \quad\left\{\mathrm{~A} \cdot \text { val }=\mathrm{A}_{1} \cdot \text { val }+1\right\} \\
\mathrm{A} \rightarrow \mathrm{~A}_{1} 0 \quad\left\{\mathrm{~A} . \operatorname{val}=\mathrm{A}_{1} \cdot \text { val }\right\} \\
\mathrm{A} \rightarrow \mathrm{~B} \quad\{\text { print }(\mathrm{A} . \text { val })\}
\end{array}
\]

The number of inherited attributes are

• A. 0
  
• B. 1
  
• C. 2
  
• D. 3

Answer 1

i think 0

none of the SDTs is deriving values from his siblings..only parent is derving from children....so no inherited attributes are present here

Comments

1st of all what this grammer do is no undersdtandable.

2nd at S -> A. how A.val = 0 updated . they take it as inherited attribute may be..

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i dont think A.val=0 is an inherited attribute... attribute which takes values form parents or sibling nodes are called inherited attributes only so none of these properties is satisfied by val here....correct me if wrong

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m not saying it is inherited . i think they considered as inherited.

Gramar what produce is not understable. they put anything